题解 | 密码强度等级

主要是耐心，按照逻辑写好if-else if语句，奖励部分将范围小的判断放前面

import java.util.Scanner;

public class Main {
    /**
     *
     *  score 分数
     *  upCount 大写字母数目
     *  lowCount 小写字母数目
     *  numCount 数字数目
     *  sigCount 符号数目
     */
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);

        while(in.hasNextLine()){
            char[] ch = in.nextLine().toCharArray();
            int score = 0;

            //统计长度
            int len = ch.length;
            if(len <= 4) score += 5;
            else if(len >4 && len < 8) score += 10;
            else score += 25;

            //遍历获取大小写字母、数字、符号数目
            int upCount = 0;
            int lowCount = 0;
            int numCount = 0;
            int sigCount = 0;

            for (int i = 0; i < len; i++) {
                if(Character.isUpperCase(ch[i])) ++upCount;
                else if(Character.isLowerCase(ch[i])) ++lowCount;
                else if(Character.isDigit(ch[i])) ++numCount;
                else ++sigCount;
            }

            //字母分数
            if((upCount > 0 && lowCount == 0) || (upCount == 0 && lowCount > 0)) score += 10;
            else if(upCount > 0 && lowCount > 0) score += 20;
            else score += 0;

            //数字分数
            if(numCount == 1) score += 10;
            else if(numCount > 1) score += 20;
            else score += 0;

            //符号分数
            if(sigCount == 1) score += 10;
            else if(sigCount > 1) score += 25;
            else score += 0;

            //奖励分数
            if (numCount > 0 && upCount > 0 && lowCount > 0 && sigCount > 0) score += 5;
            else if(numCount > 0 && sigCount > 0 &&(upCount >0 || lowCount >0)) score += 3;
            else if(numCount > 0 &&(upCount >0 || lowCount >0)) score += 2;

            //评分
            if(score >= 90) System.out.println("VERY_SECURE");
            else if(score >= 80) System.out.println("SECURE");
            else if(score >= 70) System.out.println("VERY_STRONG");
            else if(score >= 60) System.out.println("STRONG");
            else if(score >= 50) System.out.println("AVERAGE");
            else if(score >= 25) System.out.println("WEAK");
            else System.out.println("VERY_WEAK");



        }
    }
}