题解 | 牛牛的二三七整除

#include <stdio.h>


int main()
{
	int num = 0;
	int arr[3] = { 2, 3, 7 }; 
	int cnt = 0;
	scanf("%d", &num); 
	for (int i = 0; i < 3; i++)
	{
		if (num % arr[i] == 0)
		{
			printf("%d ", arr[i]);
			cnt++;
		}
		
	}
	if (cnt == 0)
	{
		printf("n\n"); 
	}
	return 0; 
}