不是很难,可以根据字符特性来判断
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while (sc.hasNext()) {
String str = sc.nextLine();
// 定义需要的结构
int eng = 0;
int space = 0;
int num = 0;
int ch = 0;
for (int i = 0; i < str.length(); i++) {
char nowChar = str.charAt(i);
if (nowChar >= 'a' && nowChar <= 'z' || nowChar >= 'A' && nowChar <= 'Z') {
eng++;
} else if (nowChar == ' ') {
space++;
} else if (nowChar >= '0' && nowChar <= '9') {
num++;
} else {
ch++;
}
}
System.out.println(eng);
System.out.println(space);
System.out.println(num);
System.out.println(ch);
}
}
}



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