题解 | #时间转换#

#include <stdio.h>

int main() {
    int seconds,a, b,c;
    scanf("%d\n",& seconds);
    if( seconds>0 && seconds<100000000)
    {
       a= seconds/60/60;
       b= seconds/60-(a*60);
       c= seconds-a*60*60-b*60;
       printf("%d %d %d",a,b,c);
    }
    
    return 0;
}