题解 | #计算一元二次方程#

while 1:
    try:
        a,b,c = map(float, input().split())
        if a == 0:
            print("Not quadratic equation")
        else:
            d = b**2-4*a*c
            if d == 0:
                print("x1=x2=%.2f" % (-b/(2*a)+0))
            elif d > 0:
                x1 = (-b-d**0.5)/(2*a)
                x2 = (-b+d**0.5)/(2*a)
                print("x1=%.2f;x2=%.2f" % (x1,x2))
            else:
                shi = -b/(2*a)+0
                xu = abs((-d)**0.5/(2*a))
                print("x1=%.2f-%.2fi;x2=%.2f+%.2fi" % (shi,xu,shi,xu))
    except:
        break