with t1 as(
select DISTINCT user_id,
sales_date,
dense_rank() over(partition by user_id order by sales_date) rk
from sales_tb
)
select user_id,max(days_count) days_count
from(
select user_id,COUNT(*) days_count
from
t1
group by user_id,date_sub(sales_date,interval rk day)
HAVINg days_count >= 2
)t2
group by user_id
ORDER BY
user_id
前提:连续签到时每天的天日期减去rk之后的值相同
首先user_id,date_sub(sales_date,interval rk day)聚合得出连续签到天数>= 2的用户
然后根据user_id聚合



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