二分模板题。
#include<bits/stdc++.h>
#define int long long
#define double long double
#define x first
#define y second
using namespace std;
typedef long long LL;
typedef long long ll;
typedef pair<int, int> PII;
const int N = 3e5 + 10;
const int M = 1e3 + 10;
int mod = 1e9 + 7;
int a[N];
void solve() {
int n, q;
cin >> n >> q;
for (int i = 0; i < n; i++)cin >> a[i];
while (q--) {
int op, l, r, x;
cin >> op >> l >> r >> x;
if (op == 1) {
int k = lower_bound(a + l, a + r , x) - a;
if (k < r&&k>=l) cout << a[k] << "\n";
else cout << -1 << "\n";
} else if (op == 2) {
int k = upper_bound(a + l, a + r , x) - a;
if (k < r&&k>=l) cout << a[k] << "\n";
else cout << -1 << "\n";
} else if (op == 3) {
int k = lower_bound(a + l, a + r , x) - a - 1;
if (k < r&&k>=l) cout << a[k] << "\n";
else cout << -1 << "\n";
} else {
int k = upper_bound(a + l, a + r , x) - a - 1;
if (k < r&&k>=l) cout << a[k] << "\n";
else cout << -1 << "\n";
}
}
}
signed main() {
ios::sync_with_stdio(false);
cin.tie(0), cout.tie(0);
int _;
_ = 1;
//cin>>_;
while (_--) {
solve();
}
}

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