题解 | #进制转换#

import sys

while True:
    try:
        str_in = input()
        str_in = str_in[2:]
        n = len(str_in)
        
        dict_ = {"A": 10, "B": 11, "C":12, "D":13, "E": 14, "F":15}

        ans = 0 
        for word in str_in:
            if word in dict_:
                tmp_ans = dict_[word]*16**(n-1)

            else:
                tmp_ans = int(word)*16**(n-1) 
            
            ans += tmp_ans
            n = n - 1
        print(ans)
    except:
        break 

dict_[word]*16**(n-1) 16进制算法 m*$进制的 n-1 次方