题解 | #KiKi和酸奶#

#include <stdio.h>

int main() {
    int n, h, m;
    while (scanf("%d %d %d", &n, &h, &m) != EOF && m <= n * h) 
    { 
        //写法1
        if(m%h == 0)
            printf("%d", n - m/h);
        else
            printf("%d", n - (m/h + 1));
            
        //写法2
        //  printf("%d", n - m/h -(m%h == 0 ? 0 : 1));
    }
    return 0;
}