题解 | 字符串构造判定

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
#
# @param ransomNote string字符串
# @param magazine string字符串
# @return bool布尔型
#
from collections import Counter

class Solution:
    def canConstruct(self, ransomNote: str, magazine: str) -> bool:
        # write code here
        return False if len(ransomNote) > len(magazine) else not (Counter(ransomNote) - Counter(magazine))