SELECT qd.difficult_level, SUM(IF (result = 'right', 1, 0)) / COUNT(qpd.device_id) AS correct_rate FROM question_detail AS qd LEFT JOIN question_practice_detail AS qpd ON qpd.question_id = qd.question_id LEFT JOIN user_profile AS up ON up.device_id = qpd.device_id WHERE up.university = '浙江大学' GrOUP BY qd.difficult_level ORDER BY correct_rate ASC;