题解 | 牛牛的计划

#include <iostream>
#include <cstdio>
using namespace std;
int main()
{
    int y,m,d,y1,m1,d1;
    cin>>y>>m>>d;
    cin>>y1>>m1>>d1;
    if(y1>y) cout<<"yes";
    else if(y1<y) cout<<"no";
    else 
    {
        if(m1>m) cout<<"yes";
        else if(m1<m) cout<<"no";
        else 
        {
            if(d1>=d) cout<<"yes";
            else cout<<"no";
        }
    }
    return 0;
}