题解 | 数字反转

#include<bits/stdc++.h>
using namespace std;

//数字反转
int reverse(int a) {
    int result = 0;
    while (a > 0) {
        int k = a % 10;
        result = result * 10 + k;
        a /= 10;
    }
    return result;
}

int main() {
    int a, b;
    while (cin >> a >> b) {
        int sum = a + b;
        if(reverse(sum) == reverse(a)+reverse(b))
        {
            cout<<sum<<endl;
        }
        else {
        cout<<"NO"<<endl;
        }
    }
    return 0;
}