本来是leetcode 一道题,环形缓冲区也是一样的设计思路,记录一下
class MyCircularQueue {
private:
vector<int> data; // 存放循环队列的数据
int head; // 循环队列头
int tail; // 循环队列尾
int len; // 循环队列的最大长度
int count; // 循环队列的元素个数
public:
/** Initialize your data structure here. Set the size of the queue to be k. */
MyCircularQueue(int k) {
data.resize(k);
head = 0;
tail = 0;
len = k;
count = 0;
}
/** Insert an element into the circular queue. Return true if the operation is successful. */
bool enQueue(int value) {
if (isFull()) {
return false;
}
data[tail] = value;
tail = (tail + 1) % len;
count++;
return true;
}
/** Delete an element from the circular queue. Return true if the operation is successful. */
bool deQueue() {
if (isEmpty()) {
return false;
}
head = (head + 1) % len;
count--;
return true;
}
/** Get the front item from the queue. */
int Front() {
if (isEmpty()) //循环队列空
{
return -1;
}
else
{
return data[head];
}
}
/** Get the last item from the queue. */
int Rear() {
if (isEmpty()) //循环队列空
{
return -1;
}
// 队尾元素位于队尾索引值减一的位置,但若队尾循环到索引 0 的位置,队尾元素位于数组最后
else
{
int temp = tail == 0 ? (len-1) : (tail-1);
return data[temp];
}
}
/** Checks whether the circular queue is empty or not. */
bool isEmpty() {
return count == 0; // 队列元素个数为零,队列空
}
/** Checks whether the circular queue is full or not. */
bool isFull() {
return count == len; // 队列元素个数为数组最大长度,队列满
}
};
/**
* Your MyCircularQueue object will be instantiated and called as such:
* MyCircularQueue obj = new MyCircularQueue(k);
* bool param_1 = obj.enQueue(value);
* bool param_2 = obj.deQueue();
* int param_3 = obj.Front();
* int param_4 = obj.Rear();
* bool param_5 = obj.isEmpty();
* bool param_6 = obj.isFull();
*/