题解 | 删除链表的节点

# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param head ListNode类 
# @param val int整型 
# @return ListNode类
#
class Solution:
    def deleteNode(self , head: ListNode, val: int) -> ListNode:
        # write code here
        dummy = ListNode(0)
        dummy.next = head
        cur = dummy
        while head:
            if head.val == val:
                cur.next = head.next
                return dummy.next
            cur = cur.next
            head = head.next
        return dummy.next