题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=6330

Problem Description

Little Q likes solving math problems very much. Unluckily, however, he does not have good spatial ability. Everytime he meets a 3D geometry problem, he will struggle to draw a picture.
Now he meets a 3D geometry problem again. This time, he doesn't want to struggle any more. As a result, he turns to you for help.
Given a cube with length a , width b and height c , please write a program to display the cube.

 

 

Input

The first line of the input contains an integer T(1≤T≤50) , denoting the number of test cases.
In each test case, there are 3 integers a,b,c(1≤a,b,c≤20) , denoting the size of the cube.

 

 

Output

For each test case, print several lines to display the cube. See the sample output for details.

 

 

Sample Input

 

2

1 1 1

6 2 4

 

 

Sample Output

 

AC代码：

#include<iostream>
#include<stdio.h>
using namespace std;
int main()
{
    int a,x,y,z,i,j,k;
    scanf("%d",&a);
    while(a--)
    {
        scanf("%d %d %d",&x,&y,&z);
        for (i = 2*y; i >0; i--)
        {
            for (j = i; j > 0; j--)
                printf(".");
            if (i%2 == 0)
            {
                for (j = 0; j < x; j++)
                    printf("+-");
                for (k = 0; k <= 2*y-i; k++)
                {
                    if (k <=2*z)
                    {
                        if ((k+i)%2 != 0)
                            printf(".");
                        else printf("+");
                    }
                    else printf(".");
                }
            }
            else
            {
                for (j = 0; j < x; j++)
                    printf("/.");
                for (k = 0; k <= 2*y-i; k++)
                {
                    if (k <= 2*z)
                    {
                        if ((k+i)%2 != 0)
                            printf("/");
                        else printf("|");
                    }
                    else printf(".");
                }
            }
            printf("\n");
        }
        for (i = max(2*(z-y)+1,1); i > 0; i--)
        {
            if (i%2 != 0)
            {
                for (j = 0; j < x; j++)
                    printf("+-");
                for (k = 0; k <= 2*y; k++)
                {
                    if (k <= 2*z)
                    {
                        if (k%2 != 0)
                            printf(".");
                        else printf("+");
                    }
                    else printf(".");
                }
            }
            else
            {
                for (j = 0; j < x; j++)
                    printf("|.");
                for (k = 0; k <= 2*y; k++)
                {
                    if (k <= 2*z)
                    {
                        if (k%2 != 0)
                            printf("/");
                        else printf("|");
                    }
                    else printf(".");
                }
            }
            printf("\n");
        }
        for (i = min(2*y,2*z); i >0; i--)
        {
            if (i%2 != 0)
            {
                for (j = 0; j < x; j++)
                    printf("+-");
                for (k = 0; k < i; k++)
                {
                    if (k <= 2*z)
                    {
                        if (k%2 != 0)
                            printf(".");
                        else printf("+");
                    }
                    else printf(".");
                }
            }
            else
            {
                for (j = 0; j < x; j++)
                    printf("|.");
                for (k = 0; k < i; k++)
                {
                    if (k <= 2*z)
                    {
                        if (k%2 != 0)
                            printf("/");
                        else printf("|");
                    }
                    else printf(".");
                }
            }
            for (j = 2*y-i+1; j > 0; j--)
                printf(".");
            printf("\n");
        }
    }
    return 0;
}