题解 | #日期累加#

#include <iostream>
using namespace std;

int GetMonthDay(int year,int month)
{
    int MonthDay[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
    if(month==2 && ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)))
    {
        return 29;
    }
    else 
    {
    return MonthDay[month];
    }
}

int main() 
{
    int a;
    cin>>a;
    while(a)
    {
        int b,c,d,e;
        cin>>b>>c>>d>>e;
        d+=e;
        while(d>GetMonthDay(b, c))
        {
            d-=GetMonthDay(b, c);
            c++;
            if(c==13)
            {
                b++;
                c=1;
            }
        }
         printf("%04d-%02d-%02d\n",b,c,d);
         a--;
    }
}
// 64 位输出请用 printf("%lld")