题干：

Little C loves number «3» very much. He loves all things about it.

Now he has a positive integer nn. He wants to split nn into 33 positive integers a,b,ca,b,c, such that a+b+c=na+b+c=n and none of the 33 integers is a multiple of 33. Help him to find a solution.

Input

A single line containing one integer nn (3≤n≤1093≤n≤109) — the integer Little C has.

Output

Print 33 positive integers a,b,ca,b,c in a single line, such that a+b+c=na+b+c=n and none of them is a multiple of 33.

It can be proved that there is at least one solution. If there are multiple solutions, print any of them.

Examples

Input

3

Output

1 1 1

Input

233

Output

77 77 79

解题报告：

  还有一个后续题目，是关于曼哈顿距离的，暂时还没学，题解先放着   我是题解

   这道题就比较水了啊，属于三元组但是却不需要这么分析，因为n太大了，1e9，所以考虑构造。

  其实也比较好构造啊，，比较容易满足题意。

#include<bits/stdc++.h>

using namespace std;

int main() 
{
	int n;
	int a,b,c;
	cin>>n;
	if(n%3==0) {
		a=1;b=1;
		c=n-a-b;
	}
	else {
		a=1,b=2;
		c=n-a-b;
	}
	printf("%d %d %d\n",a,b,c);
	return 0;
}

AC代码：