select device_id,university,count(question_id) as question_cnt,sum(new_result) as right_question_cnt from (select a.device_id,university,question_id, case when result='right' then 1 else 0 end new_result, `date` from user_profile a left join question_practice_detail b on a.device_id = b.device_id and month(b.date) = 8 where university = '复旦大学' ) as t group by device_id,university

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