题解 | 排序危机

#include <iostream>
#include <string>
using namespace std;

int main() {
    int n;
    string s;
    cin >> n >> s;
    string x, o, v;
    int a = s.size();
    for (char c : s) {
        if (c >= 'a' && c <= 'z') {
            x += c;
        } else if (c >= 'A' && c <= 'Z') {
            v += c;
        } else {
            o += c;
        }
    }
    cout << x << o << v << endl;
}
// 64 位输出请用 printf("%lld")