题解 | 排列与二进制

#include <iostream>
using namespace std;


int main() {
    int n, m;
    while (cin >> n >> m) {
        if(n == 0 && m == 0) break;
        int count = 0;
        for (int i = 0; i < m; i++) {
            int a = n;
            while (a % 2 == 0 && a != 0) {
                count++;
                a /= 2;
            }
            n--;
        }
        cout << count << endl;
    }

    return 0;
}
// 64 位输出请用 printf("%lld")