select *
from
(select
exam_id as tid,
count(distinct uid) as uv,
count(uid) as pv
from
exam_record
group by
tid
order by
uv desc,pv desc) a
union all
select *
from
(select
question_id as tid,
count(distinct uid) as uv,
count(uid) as pv
from
practice_record
group by
tid
order by
uv desc,pv desc) b



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