题解 | #X形图案#

#include <stdio.h>

int main() {
    int n;
    while (scanf("%d", &n) != EOF) 
    {
        int num;
        if (n % 2 == 0) 
        {
            num = (n - 2) / 2;
            for (int i = 1; i <= num; i++) 
            {
                for (int j = 1; j <= i - 1; j++)    //输出首部i-1个空格
                { 
                    printf(" ");
                }
                printf("*");
                for (int k = 1; k <=n - 2-2*(i-1);k++)     //输出中间n-2个空格
                { 
                    printf(" ");
                }
                printf("*");
                for (int j = 1; j <= i - 1; j++)       //输出尾部i-1个空格
                {
                    printf(" ");
                }
                printf("\n");
            }

            for(int count =1;count<=2;count++)
            {
                for(int l=1;l<=num;l++)
            {
                printf(" ");
            }
                printf("**");
                for(int l=1;l<=num;l++)
            {
                printf(" ");
            }
                printf("\n");
            }


            for (int i = 1; i <= num; i++) {
                for (int j = 1; j <= num - i; j++)     //第i行首部输出num-i个空格
                { 
                    printf(" ");
                }
                printf("*");
                for (int k = 1; k <= n-2-2*(num-i);k++)     //输出中间n-2-2*(num-i)个空格
                { 
                    printf(" ");
                }
                printf("*");
                 for (int j = 1; j <= num - i; j++)     //第i行尾部输出num-i个空格
                { 
                    printf(" ");
                }
                printf("\n");
            }

        }
        else
        {
            num = (n - 1) / 2;
            for (int i = 1; i <= num; i++) 
            {
                for (int j = 1; j <= i - 1; j++) 
                { //输出首部i-1个空格
                    printf(" ");
                }
                printf("*");
                for (int k = 1; k <= n - 2-2*(i-1);k++) 
                { //输出中间n-2*i个空格
                    printf(" ");
                }
                printf("*");
                for (int j = 1; j <= i - 1; j++) 
                { //输出尾部i-1个空格
                    printf(" ");
                }
                printf("\n");
            }
            for(int l=1;l<=num;l++)
            {
                printf(" ");
            }
            printf("*");
            for(int l=1;l<=num;l++)
            {
                printf(" ");
            }
            printf("\n");

            for (int i = 1; i <= num; i++) {
                for (int j = 1; j <= num - i; j++) 
                { //第i行输出首部num-i个空格
                    printf(" ");
                }
                printf("*");
                for (int k = 1; k <= n-2-2*(num-i);k++) 
                { //输出中间2*i个空格
                    printf(" ");
                }
                printf("*");
                   for (int j = 1; j <= num - i; j++) 
                { //第i行输出尾部num-i个空格
                    printf(" ");
                }
                printf("\n");
            }

        }


    }
}

前100道题中最长的一段代码，修改的时间和次数都创下新高，主要是关系找不正确，其次是方法比较暴力，你就说A没A吧