# 题目未说明,故未考虑一个顾客有多个订单的情况
select c.cust_name, o.order_num, oi.quantity*oi.item_price OrderTotal
from Customers c
join Orders o
on c.cust_id=o.cust_id
join OrderItems oi
on o.order_num=oi.order_num
order by c.cust_name, o.order_num;