# 题目未说明,故未考虑一个顾客有多个订单的情况 select c.cust_name, o.order_num, oi.quantity*oi.item_price OrderTotal from Customers c join Orders o on c.cust_id=o.cust_id join OrderItems oi on o.order_num=oi.order_num order by c.cust_name, o.order_num;