with t as(
select emp_no,
dept_no,
salary,
max(salary) over(partition by dept_no) as group_max
from dept_emp
left join salaries using(emp_no)
)
select dept_no,
emp_no,
salary as maxSalary
from t
where salary=group_max
构造一列每各部门的最大工资,再对比选出与最大工资相等的员工信息。

京公网安备 11010502036488号