#include<iostream>
using namespace std;
const int N = 1e3 + 10; 
int a[N][N];         
long long sum[N][N]; // 存储二维前缀和数组(用long long防止数值溢出)

int main(void) {
    int n, m, q;     
    cin >> n >> m >> q;
    for (int i = 1; i <= n; i++) {
        for (int j = 1; j <= m; j++) {
            cin >> a[i][j];
            //当前值 = 上+左-左上+当前元素
            sum[i][j] = sum[i - 1][j] + sum[i][j - 1] - sum[i - 1][j - 1] + a[i][j];
        }
    }
    for (int i = 1; i <= q; i++) {
        int x1, y1, x2, y2; // 
        cin >> x1 >> y1 >> x2 >> y2;
        // 大区域 - 上侧区域 - 左侧区域 + 重复减去的左上区域
        cout << sum[x2][y2] - sum[x1 - 1][y2] - sum[x2][y1 - 1] + sum[x1 - 1][y1 - 1] <<
             endl;
    }

    return 0;
}