select C. name as customer_name, sum(P.price) as total_travel_cost, count(B.customer_id) as order_count, round(sum(P.price)/count(B.customer_id), 2) as avg_order_price from bookings B join packages P on P.id = B.package_id join customers C on C.id = B.customer_id where year(booking_date) = 2024 group by C. name having sum(P.price) > 10000 order by sum(P.price) desc



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