贪心算法——鸡兔同笼

#include <iostream>
#include <cstdio>

using namespace std;

int main(){
    int a;
    while(scanf("%d",&a)!=EOF){
        int MinNumber=0;
        int MaxNumber=0;
        if(a%2==0){                //总脚数为偶数，该问题才有解,无解情况不用考虑解情况
            MinNumber=a/4+(a%4)/2;     //先处以4，余数用鸡来代替
            MaxNumber=a/2;
        }
        printf("%d %d",MinNumber,MaxNumber);
    }
    return 0;
}