with sum_class_grade as (
select
grade,
(select sum(number) from class_grade) as total,
sum(number) over (order by grade) as sum,
sum(number) over (order by grade desc) as sum_desc
from
class_grade
)
select
grade
from
sum_class_grade
where
sum >= round(total / 2 ,0)
and
sum_desc >= round(total / 2 ,0)
order by
grade


京公网安备 11010502036488号