with avg_score as ( select department_name,avg(performance_score) as avg_score from department_info d join employee_projects e on e.employee_id =d.employee_id group by department_name ) select d.employee_id,d.department_name,performance_score from department_info d join employee_projects e on e.employee_id =d.employee_id join avg_score a on d.department_name=a.department_name where performance_score>avg_score order by d.employee_id;

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