不独特的人就不独特,直接输出,而独特的人就让他们去坐下一个独特的人的座位就可以了,最后一个独特的人坐第一个人的位置。
#include <iostream> #include <queue> #include <map> #include <set> #include <cmath> #include <cstring> #include <algorithm> #include <iomanip> #include <stack> #include <numeric> #include <ctime> #include <string> #include <bitset> #include <unordered_map> #include <unordered_set> using namespace std; using ll = long long; const ll N = 1e5 + 5, mod = 1e9 + 7, inf = 0x3f3f3f3f; int n, a[N]; void solve() { cin >> n; string s; cin >> s; map<int, int>mp; vector<int>ve; for (int i = 0; i < n; i++) { if (s[i] == '0')a[i + 1] = i + 1; else { ve.push_back(i + 1); } } for (int i = 0; i < ve.size() - 1; i++) { mp[ve[i]] = ve[i + 1]; } mp[ve.back()] = ve[0]; for (int i = 1; i <= n; i++) { cout << (a[i] ? a[i] : mp[i]) << " "; } } int main() { ios::sync_with_stdio(0), cin.tie(0), cout.tie(0); int t = 1; //cin>>t; while (t--) { solve(); } return 0; }