题解 | #二进制数#

#include<iostream>
using namespace std;

int main(){
	long long n;
	while(scanf("%d",&n)!=EOF){
		int res[10000];     //存放二进制数
		int count=0;
		while(n!=0){
			res[count++]=n%2;
			n/=2;
		}
        
		for(int i=count-1;i>=0;i--){   //从高位到低位输出
			cout<<res[i];
		}
        cout<<endl;
	}
	return 0;
}