一个思路清晰的分步骤解题思路
这道题难也难不到哪去,就是比较复杂,代码多了遇到点小错误容易改崩溃,比如StringBuilder设的是全局的,但是局部用过一次没有及时清空导致答案非常离谱。。。
import java.util.*;
import java.util.*;
public class Main{
public static void main(String[] args){
Scanner scanner = new Scanner(System.in);
String s1 = scanner.next();
String s2 = scanner.next();
s1 = convert(asort(combine(s1,s2)));
System.out.println(s1);
}
public static String combine(String str1, String str2){
String str3 = str1 + str2;
return str3;
}
public static String asort(String str){
int len = str.length();
StringBuilder odd = new StringBuilder();
StringBuilder even = new StringBuilder();
for(int i = 0; i < len; i++ ){
if(i % 2 == 0)
odd.append(str.charAt(i));
else
even.append(str.charAt(i));
}
String oddStr = odd.toString();
String evenStr = even.toString();
char[] oddChar = oddStr.toCharArray();
char[] evenChar = evenStr.toCharArray();
Arrays.sort(oddChar);
Arrays.sort(evenChar);
StringBuilder sb1 = new StringBuilder();
for(int i = 0; i < len; i++){
if(i % 2 == 0)
sb1.append(oddChar[i / 2]);
else
sb1.append(evenChar[(i + 1) / 2 - 1]);
}
oddStr = sb1.toString();
return oddStr;
}
public static String convert(String str){
StringBuilder sb = new StringBuilder();
StringBuilder sb1 = new StringBuilder();
String s;
for(int i = 0; i < str.length(); i++){
int j = 0;
if(str.charAt(i) >= '0' && str.charAt(i) <= '9'){
s = new StringBuilder(Integer.toBinaryString(Integer.parseInt(str.charAt(i) + ""))).toString();
while(j++ < (4 - s.length()))
sb.append('0');
sb.append(s);
s = sb.reverse().toString();
sb.delete(0,sb.length());
int num = Integer.parseInt(s,2);
sb1.append(Integer.toHexString(num).toUpperCase());
}
else if(str.charAt(i) >= 'a' && str.charAt(i) <= 'f'){
s = str.charAt(i) - 'a' + 10 + "";
s = new StringBuilder(Integer.toBinaryString(Integer.parseInt(s))).toString();
sb.append(s);
s = sb.reverse().toString();
sb.delete(0,sb.length());
int num = Integer.parseInt(s,2);
sb1.append(Integer.toHexString(num).toUpperCase());
}
else if(str.charAt(i) >= 'A' && str.charAt(i) <= 'F'){
s = str.charAt(i) - 'A' + 10 + "";
s = new StringBuilder(Integer.toBinaryString(Integer.parseInt(s))).toString();
sb.append(s);
s = sb.reverse().toString();
sb.delete(0,sb.length());
int num1 = Integer.parseInt(s,2);
sb1.append(Integer.toHexString(num1).toUpperCase());
}
else{
sb1.append(str.charAt(i));
}
}
return sb1.toString();
}
}