# 思路：使用where限制查询结果为非manager员工，然后查询剩下员工的薪水
select dept_no, k1.emp_no, salary
from (
    select emp_no from employees 
    where emp_no not in (select distinct emp_no from dept_manager)
) k1
join dept_emp de
on k1.emp_no = de.emp_no
join salaries s
on k1.emp_no = s.emp_no