题解 | #牛牛的计划#

#include <stdio.h>

int main() {
    int a,b,c,d,e,f;
    scanf("%d %d %d",&a,&b,&c);
    scanf("%d %d %d",&d,&e,&f);
    if(d>a){printf("yes");}
    else if(d==a){
       if(e>b){printf("yes");}
       else if(e==b){
         if(f>=c){printf("yes");}
         else printf("no");
       }
       else printf("no");
    }
    else printf("no");
    return 0;
}