题解 | #字符串的反码#

#include<iostream>
using namespace std;
int main() {
    string s;
    while(cin >> s)
    {
        for(int i = 0; i < s.length(); i++)
        {
            //小写
            if(s[i] >= 'a' && s[i] <= 'z')
            {
                s[i] = 'z' + 'a' - s[i];
            }

            //大写
            if(s[i] >= 'A' && s[i] <= 'Z')
            {
                s[i] = 'Z' + 'A' - s[i];
            }
        }
        cout << s << endl;
        return 0;
    }
}