题解 | #确定最佳顾客的另一种方式（二）#

select Customers.cust_name, sum(OrderItems.item_price*OrderItems.quantity) total_price from Orders inner join OrderItems on Orders.order_num = OrderItems.order_num inner join Customers on Orders.cust_id = Customers.cust_id group by Customers.cust_name having total_price>=1000 order by total_price