题解 | #单词消消乐#

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param Words string字符串一维数组 
# @return string字符串
#
class Solution:
    def WordsMerge(self , Words ):
        # write code here
        def mergetwo(w1, w2):
            stack = list(w1)
            n = len(w2)
            for i in range(n):
                if w2[i] == stack[-1]:
                    stack.pop()
                    tmp = w2[i+1:]
                else:
                    tmp = w2[i:]
                    break
            res = "".join(stack) + tmp
            return res
        
        if not Words:
            return ""

        w1 = Words[0]
        for i in range(1, len(Words)):
            w1 = mergetwo(w1, Words[i])
        return w1