题解 | 最大最小值 max(x,y)=(x+y+|x-y|)/2

#include <stdio.h>
int abs(int x){
    return x<0?-x:x;
}int max(int x,int y){
    return(x+y+abs(x-y))/2;
}int min(int x,int y){
    return(x+y-abs(x-y))/2;
}
int main() {
    int a, b,c;
    while (scanf("%d %d %d", &a, &b,&c) != EOF) { // 注意 while 处理多个 case
        // 64 位输出请用 printf("%lld") to 
        int maxn=max(max(a,b),c);
        int minn=min(min(a,b),c);
        
    printf("The maximum number is : %d\n",maxn);
    printf("The minimum number is : %d\n", minn);
    
    }
    return 0;
}