题解 | 时间转换

#include <stdio.h>

int main() 
{
    long long s;
    int h,m,j,n;
    scanf("%lld",&s);
    if(s>=3600)
    {
        h=s/3600;
        m=s%3600;
        if(m>60)
        {
            j=m/60;
            n=m%60;
            printf("%d %d %d\n",h,j,n);
        }
        else {
        printf("%d 0 %d\n",h,m);
        }
    }
    else {
    if(s>=60)
    {
        j=s/60;
        n=s%60;
        printf("0 %d %d\n",j,n);
    }
    else {
    printf("0 0 %d\n",s);
    }
    }
    return 0;
}