#python解法 while True: try: n = int(input()) for i in range(n): s = input() dic_s = {} for i in s: #计算字符串中各个字母出现的次数并存放在字典中 if i not in dic_s: dic_s[i] = 1 else: dic_s[i] += 1 #对字典按照字母出现的次数从大到小排序 m = sorted(dic_s.items(),key = lambda x:-x[1]) n,index = 0,0 for i in m: n = n + i[1] * (26-index) index += 1 print(n) except: break