题解 | 在二叉树中找到两个节点的最近公共祖先

# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param root TreeNode类 
# @param o1 int整型 
# @param o2 int整型 
# @return int整型
#
class Solution:
    def lowestCommonAncestor(self , root: TreeNode, o1: int, o2: int) -> int:
        # write code here
        if not root:
            return None
        if root.val == o1 or root.val == o2:
            return root.val
        left = self.lowestCommonAncestor(root.left, o1, o2)
        right = self.lowestCommonAncestor(root.right, o1, o2)
        if left and right:
            return root.val
        return left if left else right