题解 | #打印等腰三角形#

#!/bin/bash
read n
for ((i = 1; i <= $n; i++)); do
	# 打印空格
	for ((j = $n - i; j >= 1; j--)); do
		printf " "
	done
	# 打印星星
	for ((k = 1; k <= i; k++)); do
		printf "* "
	done
	printf "\n"
done