题解 | 凯撒加密

#include <iostream>
using namespace std;

int main() {
    int n;
    string str;
    cin>>n;
    cin>>str;
    n = n%26;
    for(auto &c:str)
    {
        if((c+n)>'z')
            c='a'+c+n-'z'-1;
        else
           c=c+n;
    }
    cout<<str;
}
// 64 位输出请用 printf("%lld")