ZOJ Problem Set - 4016

链表操作，数组实现，其中记得要保存链表的头

参考代码

#include<bits/stdc++.h>

using namespace std;

const int maxn = 1e6+100;
int shu[maxn];
int point[maxn];
int pre[maxn];
int First[maxn];
int sz;
void Insert(int x,int n)
{
    shu[sz] = n;
    if(point[x] == 0)
        First[x] = sz;
    pre[sz] = point[x];
    point[x] = sz;
    sz++;
}
void Pop(int x)
{
    if(point[x] == 0)
    {
        printf("EMPTY\n");
        return ;
    }
    int t = point[x];
    printf("%d\n",shu[t]);
    point[x] = pre[t];
}
void Move(int t,int s)
{
    if(point[t] == 0)
        return ;
    if(First[s] == 0)
        First[s] = First[t];
    pre[First[t]] = point[s];
    point[s] = point[t];
    point[t] = 0;
    First[t] = 0;
}
int main()
{
    int T;
    scanf("%d",&T);
    while(T--)
    {
        int n,m;
        scanf("%d %d",&n,&m);
        for(int i = 1; i <= n; ++i)
            point[i] = 0,First[i] = 0;
        sz = 1;
        while(m--)
        {
            int op;
            int a,b;
            scanf("%d",&op);
            if(op == 1)
            {
                scanf("%d %d",&a,&b);
                Insert(a,b);
            }
            else if(op == 2)
            {
                scanf("%d",&b);
                Pop(b);
            }
            else
            {
                scanf("%d %d",&a,&b);
                Move(b,a);
            }
        }
    }



    return 0;

}

通过STL的list 也可以实现，有兴趣的可以百度一下