题解 | #翻转金字塔图案#

#include <stdio.h>
int main() {
    int n = 0;
    while (scanf("%d", &n) != EOF) {
        int m = 0;
        m = n;
        //一行一行的打印
        int i = 0;
        for (i = 0; i < n; i++) {
            int j = 0;
            int k = 0;
            for (k = n; k > m; k--) {
                printf(" ");
            }
            for (j = 0; j < k; j++) {
                printf("%c ", '*');
            }
            printf("\n");
            m--;
        }
    }
    return 0;
}