题解 | 判断两个IP是否属于同一子网

t = list(map(int, input().split('.')))
s1 = list(map(int, input().split('.')))
s2 = list(map(int, input().split('.')))


def f2(s):
    p = '1'
    cnt = 0
    for x in s:
        if x != p:
            cnt += 1
        p = x
    return cnt <= 1
def f1(nums):
    for x in nums:
        if x < 0 or x > 255:
            return False
    return True


def cal(nums1, nums2):
    ans = []
    for x, y in zip(nums1, nums2):
        ans.append(x & y)
    return ans


tt = ''
for x in t:
    d = bin(x)[2:]
    m = len(d)
    tt += '0' * (8 - m) + d

if not f1(t) or not f1(s1) or not f1(s2) or not f2(tt):
    print(1)
    exit()

a1 = cal(t,s1)
a2 = cal(t,s2)

# print(a1,a2,tt)
if not f1(a1) or not f1(a2):
    exit(print(1))

if a1 == a2:
    print(0)
else:
    print(2)

对输入字符串进行.分割，

然后分别检验三个码是否规范，不规范范围1

否则判断与运算后是否符合规范

返回对应的值

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