题解 | #字母统计#

#include <stdio.h>
#include <string.h>
int main(){
    char arr[100];  //输入的最大长度
    scanf("%s", arr);
    int len = strlen(arr);
    int num;
    int count[91] = {0};    //只有65-90有用
    for (int i = 65; i <= 90; ++i) {    //A-Z对应为65-90
        for (int j = 0; j < len; ++j) {
            num = arr[j];   //把字符转化为对应的ASCII码
            if (num == i){
                count[i]++;
            }
        }
    }
    for (int i = 65; i <= 90; ++i) {
        printf("%c:%d\n", i, count[i]);
    }
    return 0;
}