题解 | #计算日期到天数转换#

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>

int main() {
    int a, b;
    int year, month, day;
    int sum = 0;
    scanf("%d %d %d", &year, &month, &day);
    int days[] = { 31,28,31,30,31,30,31,31,30,31,30,31 };//平年
    int days2[] = { 31,29,31,30,31,30,31,31,30,31,30,31 };//闰年
    for (int i = 1; i < month; i++)
    {
        if ((year % 400 == 0) || ((year % 100 != 0) && (year % 4 == 0)))
        {
            sum += days2[i - 1];
        }
        else
            sum += days[i - 1];
    }
    printf("%d", sum + day);
    return 0;
}