题解 | #井字棋#

#include <iostream>

using namespace std;

int main()
{
    char arr[3][3] = { {'o'} };
    int count1 = 0, count2 = 0;
    int count3 = 0, count4 = 0;

    for (int i = 0; i < 3; i++)
    {
        for (int j = 0; j < 3; j++)
        {
            cin >> arr[i][j];
        }
    }
    for (int i = 0; i < 3; i++)
    {
        if (arr[i][0]=='K'&&arr[i][1]=='K'&&arr[i][2]=='K')
        {
            cout << "KiKi wins!" << endl;
            return 0;
        }
        else if (arr[i][0] == 'B' && arr[i][1] == 'B' && arr[i][2] == 'B')
        {
            cout << "BoBo wins!" << endl;
            return 0;
        }
        else if (arr[0][i] == 'K' && arr[1][i] == 'K' && arr[2][i] == 'K')
        {
            cout << "KiKi wins!" << endl;
            return 0;
        }
        else if (arr[0][i] == 'B' && arr[1][i] == 'B' && arr[2][i] == 'B')
        {
            cout << "BoBo wins!" << endl;
            return 0;
        }
        else if (arr[i][i] == 'K')
        {
            count1++;
        }
        else if (arr[i][i] == 'B')
        {
            count2++;
        }
    }
    if (count1 != 3 || count2 != 3)
    {
        for (int i = 0; i < 3; i++)
        {
            for (int j = 0; j < 3; j++)
            {
                if (i + j == 2)
                {
                    if (arr[i][j] == 'K')
                    {
                        count3++;
                    }
                    else if (arr[i][j] == 'B')
                    {
                        count4++;
                    }
                }
            }
        }
    }
    
    if (count1 == 3 || count3 == 3)
    {
        cout << "KiKi wins!" << endl;
    }
    else if (count2 == 3 || count4 == 3)
    {
        cout << "BoBo wins!" << endl;
    }
    else
    {
        cout << "No winner!" << endl;
    }
    return 0;
}